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Completed Array-1#1985

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Completed Array-1#1985
Sanket-S-Kale wants to merge 1 commit into
super30admin:masterfrom
Sanket-S-Kale:master

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Product Except Self (Problem1.py)

Strengths:

  1. Correct Algorithm Choice: The two-pass approach is the optimal solution for this problem, achieving O(n) time complexity.
  2. Clear Documentation: The docstring explains the logic well, including time and space complexity analysis.
  3. Clean Code Structure: The code is well-organized with clear comments separating the two passes.
  4. Efficient Space Usage: Only uses a few integer variables (rp, n) plus the required output array.

Areas for Improvement:

  1. Variable Naming: rp could be more descriptive (e.g., running_product or right_product), though this is minor.
  2. Edge Case Handling: The solution assumes n > 1, which matches constraints, but could benefit from a brief comment noting this.
  3. Import Statement: The List type hint requires importing from typing, which should be included at the top of the file.

Comparison to Reference:

  • The reference solution uses O(n²) time complexity with nested loops, while the student's solution achieves the required O(n) time complexity.
  • The reference solution claims O(1) space but actually uses O(n) due to the output array; the student's solution correctly accounts for this distinction.

VERDICT: PASS


Diagonal Traverse (Problem2.py)

Evaluation

Correctness

The student's solution correctly implements the diagonal traversal algorithm. It handles all boundary conditions properly:

  • When moving up-right and hitting the right edge or top edge, it switches direction
  • When moving down-left and hitting the bottom edge or left edge, it switches direction
  • The algorithm visits every element exactly once and produces the correct output sequence

Time Complexity

Both solutions have O(m × n) time complexity, visiting each element exactly once. The student's solution is equally efficient.

Space Complexity

Both solutions use O(1) auxiliary space (excluding the output array). The student's solution follows the same pattern as the reference.

Code Quality

The student's solution is excellent in terms of code quality:

  • Clear and descriptive variable names (numRows, numCols, isGoingUp)
  • Well-documented with a comprehensive docstring explaining the logic
  • Proper handling of edge cases (empty matrix check)
  • Consistent indentation and readable structure
  • Comments explaining each condition block

Efficiency

The solution is already optimal. The boundary condition checks are efficient and the algorithm follows the standard approach for this problem.


Feedback

Strengths:

  • Excellent documentation with detailed explanation of the algorithm logic
  • Clean, readable code with meaningful variable names
  • Proper edge case handling (empty matrix)
  • Well-structured conditional logic that's easy to follow
  • Comprehensive time and space complexity analysis in the docstring

Areas for Improvement:

  • The solution is already well-optimized. Minor observations:
    • Could potentially combine some conditions using or, but the current explicit approach is more readable
    • The isGoingUp variable name is slightly verbose; dir (as in reference) is more concise, but readability is generally preferred

The student's solution is correct, efficient, and demonstrates a solid understanding of the problem. The code quality is excellent with comprehensive documentation. This solution is on par with the reference solution and shows good programming practices.

VERDICT: PASS


Spiral Matrix (Problem3.py)

Strengths:

  1. Clean and well-structured code with clear comments explaining each traversal step
  2. Proper handling of boundary conditions to avoid index out of bounds or duplicate elements
  3. Good variable naming (left, right, top, bottom) that makes the logic easy to follow
  4. Correct time complexity of O(m*n) matching the reference solution
  5. Efficient space usage with O(1) auxiliary space (excluding output array)

Areas for Improvement:

  1. The variable naming is slightly inconsistent - left, top = 0, 0 and right, bottom = n - 1, m - 1 could be more uniformly structured
  2. Could add type hints for better code documentation (e.g., def spiralOrder(self, matrix: List[List[int]]) -> List[int]:)
  3. The solution is functionally equivalent to the reference but could benefit from a brief docstring explaining the algorithm

The solution is correct, efficient, and well-written. It demonstrates a solid understanding of the spiral matrix problem.

VERDICT: PASS

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